If n becomes 1 then it is a power of 2. Distance = 5 – 3 = 2. Hence there are 2 refueling stops along the way. Examples :Practice. Input: N = 4, arr [] = [1 3 2 4] Output: 3 4 4 -1. Submit. Beginner's DSA Sheet; Love Babbar Sheet; Top 50 Array Problems; Top 50 String Problems; Top 50 DP Problems; Top 50 Graph Problems; Top 50 Tree Problems; Contests. Reverse every sub-array group of size K. GfG Weekly + You = Perfect Sunday Evenings! Given an array with repeated elements, the task is to find the maximum distance between two occurrences of an element. If next is greater than the top element, Pop element from stack. NearestGreaterToLeft (A) 1. Given a binary matrix of order m*n, the task is to find the distance of the nearest 1 for each 0 in the matrix and print the final distance matrix. When an inversion is found, two values are swapped and the process is repeated. Input and output is handled for you. Minimize the Heights II. Next Greater Element III - Given a positive integer n, find the smallest integer which has exactly the same digits existing in the integer n and is greater in value than n. You need to find if two numbers in A exists that have sum equal to the given sum. Pender Island, BC V0N 2M1. Optimal Substructure: When we drop an egg from floor x, there can be two cases (1) The egg breaks (2) The egg doesn’t break. Given an array arr [ ] of size N having elements, the task is to find the next greater element for each element of the array in order of their appearance in the array. Back to Explore Page. Assign left[i] = -1 and right[i] = N; Traverse a loop on i from 0 till N. Platform to practice programming problems. 72, 0. Mark the current element as next. Smaller number than 6 and 2 is 1. You. Stop the inner loop when you see an element greater than the picked element and keep updating the maximum j-i so far. Try It!. else if not stack is empty 6. Determine whether or not there exist two elements in Arr whose sum is exactly X. Next greater element of an element in the array is the nearest element on the right which is greater than the current element. Example 1: Input: N = 6, X = 16 Arr [] = {1, 4, 45, 6, 10, 8} Output. The second largest element is second last element in inorder traversal and second element in reverse inorder traversal. Hoare’s Partitioning: It works by initializing two indexes that start at two ends, the two indexes move toward each other until an inversion is (A smaller value on the left side and a greater value on the right side) found. Next greater element of an element in the array is the nearest element on the right which is greater than the current element. Given a positive integer . Coding and decoding questions are a. You don't need to read input or print. We traverse given Binary Search Tree in reverse inorder and keep track of counts of nodes visited. 1. Notice that it is the combination of Next greater element & next smaller element in array. All DSA Problems; Problem of the Day; GFG SDE Sheet; Curated DSA Lists. 4. Next Greater Element II - LeetCode. Example 1: Input: arr [] = {8, 58, 71, 1. Example 1: Input: N. Given two linked lists, your task is to complete the function makeUnion (), that returns the union list of two linked lists. Then search maximum node between LCA and ‘a’, and also find the maximum node between LCA and ‘b’. left==None and root. We have discussed two stack-based solutions: 1) Traversing from left to right, 2) Traversing from right to left. Time Complexity: O(N 2) Auxiliary Space: O(1) Efficient Approach: The. So first take greatest number 6 then the lower number 2. Initialize a variable mid with l+ (r-l)/2. Follow the steps below to solve the problem: Initialize a variable, ans with 0 for storing the result. Idea/Intuition : Make a temporary array same as the given array ,sort the temporary array . More formally, G [i] for an element A [i] = an element A [j] such that j is minimum possible AND j. For 7, 5 is the greatest element in its left. The smallest digit greater than 4 is 6. A Segment Tree is a data structure that stores information about array intervals as a tree. Approach: Let's round down the given number n to the nearest integer which ends with 0 and store this value in a variable a. If the stack is not emptyGiven an array of N positive integers, print k largest elements from the array. Given an array, print the Next Greater Element (NGE) for every element. Example 1: Input: str = "a. Beginner's DSA Sheet; Love Babbar Sheet; Top 50 Array Problems; Top 50 String Problems; Top 50 DP Problems; Top 50 Graph Problems; Top 50 Tree Problems; Contests. length - 1] is nums[0]), return the next greater number for every element in nums. Input: str = “99999999999999996”. Explanation: 9 is the divisor of 27 closest to 15. Now check from starting at which index the element of the given array and temporary array are unequal and store it in temporary variable s . Example 1: Input: nums = [5,2,6,1] Output: [2,1,1,0] Explanation: To the right of 5 there are 2 smaller elements (2 and 1). Traverse the tree and compare root data with x. data,root. The number 139. Convert this infix expression to postfix expression. Console. Given a sorted array Arr of size N and a number X, you need to find the number of occurrences of X in Arr. This is the best place to expand your knowledge and get prepared for your next interview. A close upper bound on time complexity of this solution is O(10 m). Video. For 17 it's 5. Approach: To solve the problem follow the below idea: Finding the next greater element in a binary search tree involves performing an in-order traversal of the tree to create a sorted list of its node values. If there’s no such element, return -1 for this number. If there does not exist next greater of current element, then next greater element for current element is -1. java. Traverse node by node (Inorder, preorder, etc. Given an array arr [] of N non-negative integers representing the height of blocks. Jobs. Given a sorted array, and an element x to be searched, find position of x in the array. When an operator is followed for every pair of operands. The next greater element of a number x is the first greater number to its traversing order next in. It consists of the following three steps: Divide. In any iteration, if n%2 becomes non-zero and n is not 1 then n is not a power of 2. Traverse the array and shift the digits of array elements in all possible ways and pick the one which is minimum, but greater than the previous array element. ie- the traversal must begin from the last level. and so on. For 2, stack is not empty so we have to check the top most value if it is smaller than 2 or not. return the minimum energy that can be used by the Geek to jump from stair 0 to stair N-1. A height balanced tree 1 / 10 39 / 5. (3) Divide the number n into two parts i. Submit. Example 2:Given a number N. The least next greater element of 58 is 63 and so on. In the outer loop, pick elements one by one and in the inner loop calculate the difference of the picked element with every other element in the array and compare the. Hence, the total time complexity of the approach becomes O(n log n). vscode","path":". length - 1] is nums[0]), return the next greater number for every element in nums. Store all these sums. 8) Find log base 2 of 32 bit integer. For 10, there are three smaller elements on left side (1, 6 and 4), nearest among the three elements is 4. The smaller power of K will be the floor value (say X) of logKN. class 5 practice test - Passenger Vehicle. (4) Loop for i in range (mid): (a) Remainder of first_half by 10 add it to the multiplication of 10 and rev1. Drive to position 10, expanding 10 units of fuel. The function takes a string(str) as argument and converts it to an integer and returns it. , the next element of arr [N-1] is arr [0] ), return the next greater number for every element in arr. Can you solve this real interview question? Next Greater Element II - Level up your coding skills and quickly land a job. Otherwise, if node’s value is greater than or equal to N and left. Replace each node value with their corresponding sum by traversing in the same order as in Step 1. Idea/Intuition : Make a temporary array same as the given array ,sort the temporary array . Rearrange array such that even positioned are greater than odd;. Example 1: Input: N = 7 Arr[] = {12, 1, 2, 3, 0, 11, 4} Output: 6 1 1 1 0 1 0 Explanation: There are 6 elements right after 12. Input n= 6 arr = {1, 1, 2, 2, 2, 1} Output 5 Explanation arr [] = {1, 1, 2, 2, 2, 1} Max Distance: 5 Distance for 1 is: 5-0 = 5 Distance for 2 is. Below. Note: If the difference is same for two values print the value which is greater than the given number. Divide and Conquer Algorithm: This algorithm breaks a problem into sub-problems, solves a single sub-problem and merges the solutions together to get the final solution. Step 5:Repeat the same procedure to find the next greater element for each element. Minimize operations to make all elements equal by replacing left half of Subarray with right half. If root data is greater than x, increment the count variable and recursively call for all its children. If a [] has no greater element than b [i], then value of c [i] is -1. From any cell (i,j), we can move only in four directions up, down, left and right. Do the same thing but going from right to left. Brute Force Approach: A simple approach is to start from the first interval and compare it with all other intervals for overlapping, if it overlaps with any other interval, then remove the other interval from the list and merge the other into the first interval. We can solve above problem by following approach – For each point p, calculate its slope with other points and use a map to record how many points have same slope, by which we can find out how many points are on same line with p as their one point. similar to nearest greater to left using stack - undefined - LeetCode. Distance = 2 – 1 = 1. (250). Source: Puzzle 22 | (Maximum Chocolates) A naive method is to continuously count the number of chocolates by returning wrappers until wrappers left didn’t become less than required to. Array may contain duplicate values. And then while merging back we sort them in decreasing order and keep track of count the smaller elements. If stack is not empty, compare top element of stack with next. Input: N = 4, arr [] = [1 3 2 4] Output: 3 4 4 -1. Menu. ;. For 5, 4 is the greatest element in its left. Example 2: Input: N = 1500 Output: 1521 21 Explanation: Two of the. We use a stack. Algorithm. The next greater number of a number x is the first greater number to its traversing-order next in the array, which means you could search circularly to find its. Explanation: 19 is the smallest element greater than 18. Easy programming puzzles. The idea is use BFS or DFS. Use the floor () function to get the integer part of the result. Method 2 (Using Stack) Push the first element to stack. Let k be. Since there is no element next to the last element, replace it with -1. "Next greater element on the left" of an element x is defined as the first element to left of x having value greater than x. Given a sorted array Arr of size N and a value X, find the number of array elements less than or equal to X and elements more than or equal to X. a += b. Nearest Smaller Element - Given an array, find the nearest smaller element G[i] for every element A[i] in the array such that the element has an index smaller than i. Back to Explore Page. For each tower, you must perform exactly one of the following operations exactly once. Instructions from Interviewbit. Approach 1 : (Brute Force Method) A brute force approach to this problem can be, keep a variable idx = -1 from beginning and for each element start traversing the same array from the backward upto (i+1)th index. Following are the steps. 3 elements arranged at positions 1, 7 and 12, resulting in a minimum distance of 5 (between 7 and 12) A Naive Solution is to consider all subsets of size 3 and find the minimum distance for every subset. Below is the implementation of the above idea. {"payload":{"allShortcutsEnabled":false,"fileTree":{"":{"items":[{"name":". If the element is the leftmost element, neare. If no small element present on the left print -1. Once we find an element that is greater than the previous element, we know that the maximum element has been. 4) Find the index of maximum element in count array. 2305 Otter Bay Road. Your task is to complete the function print_next_greater_freq () which take two parameters arr and n. The Next greater element for an element x is the first greater element on the right side of x in the array. An easy approach is simple brute force: count the number of 1s in n, and then increment (or decrement) until we find a number. The task is to complete the function isPalindrome() which takes head as reference as the only parameter and returns true or false if linked list is palindrome or not respectively. Examples: Input: A = 459, B = 500. Solve Problems. Naive approach: A Simple Solution is to consider every index ‘i’ and do the following. The practice system tells you exactly the test case where your code failed. Given an array of integers, find the closest (not considering the distance, but value) greater or the same value on the left of every element. Then simply drive and reach the target. We can get the nearest smaller or greater element depending on the monotonic stack type, by just retrieving the stack’s top element, which is just an O(1) operation. Method 2 (Using Stack) Push the first element to stack. 78, 0. Sort all the elements of the input array. If no such positive integer exists, return -1. 1- if stack is empty, push current index. left++ b. For the arr [1] and arr [2] no element on the right has greater frequency than 1, so -1 will be printed. The K-NN algorithm works by finding the K nearest neighbors to a given data point based on a distance metric, such as Euclidean distance. Distance = 6 – 2 = 4. 2. Hi Friend Today we are solving a new programming interview question on the stack is called - Next Largest Element To Left in the array or Nearest Greater To. Program for array left rotation by d positions. So the value will be pow (K, X). Given a positive number n (n > 1), round-off this number to a given no. Pick rest of the elements one by one and follow the following steps in loop. Examples: Input: N = 1500 Output:. If (root. Next greater element of an element in the array is the nearest element on the right which is greater than the current element. Else, move right pointer one step to the left, i. Given an array arr[] denoting heights of N towers and a positive integer K. Clearing the DSA round for the Interviews, as these are the questions generally asked in the companies like Amazon, Microsoft,. least next greater element for 9 does not exist and so on. Constraints: m != 0. A Simple Solution is to consider all m digit numbers and keep track of minimum number with digit sum as s. Example 1: Input: str = "a+b* (c^d-e)^ (f+g*h)-i" Output: abcd^e-fgh*+^*+i- Explanation: After converting the infix expression into postfix. ) For each node find all the nodes greater than that of the current node, sum the values. Traverse the array arr [] using the variable i. GFG Weekly Coding Contest; Job-A-Thon: Hiring Challenge; All. Call ‘countNodes’ function with the root node of the binary tree and ‘K’ as inputs. Given an array, find the next greater element for every element in the array (NGE). Approach 2: Using Dynamic Programming: Firstly, divide the entire array into blocks of k elements such that each block contains k elements of the array (not always for the last block). For 13, there is already an element in the stack which is greater than 13 so that will be the inserted into the output array and 13 will be pushed into the stack. The name of this searching algorithm may be misleading as it works in O (Log n) time. There are 1 element right after 1. Pick rest of the elements one by one and follow the following steps in loop. 1) Find the middle point in the sorted array, we can take P [n/2] as middle point. *=. Lower Bound – Let L(n) be the running time of an algorithm A(say), then g(n) is the Lower Bound of A if there exist two constants C and N such that L(n) >= C*g(n) for n > N. Iterate through the linked list and insert the value and position of elements of the linked list into a stack. Feeling lost in the world of random DSA topics, wasting. Like Article. Two Sum Using remainders of the elements less than x: The idea is to count the elements with remainders when divided by x, i. Examples: Input : n = 5 Output : Closest Greater = 6 Closest Smaller = 3 Note that 5, 6 and 3 have same number of set bits. Time Complexity: O(x) Auxiliary Space: O(1) An Efficient Solution can solve this problem in O(k) time where k is number of Jumping Numbers smaller than or equal to x. Reddit. Below is the main rotation code of a subtree. Find the next larger element to the left in an array. 3) Keep. Given a sorted array Arr of size N and a value X, find the number of array elements less than or equal to X and. VMWare. The main point to note here is that a closest key can either be a descendant of given key or can be reached through one of the ancestors. Step 2:Start the inner loop from i+1 to the size of the array. Run a loop till the size of the queue is greater than 0 then extract the front node of the queue and remove it and insert all its adjacent and unmarked elements. Given a singly linked list of size N of integers. Given an array arr, replace every element in that array with the greatest element among the elements to its right, and replace the last element with -1. Now for every element in matrix update element with max value which can be included in max path. Output: tbacaf. for zero, on left 4th element is closest and greater than zero and on right 6th element is closest and greater. Solve DSA problems on GfG Practice. Example 1: Input: N = 25 Output: 25 0 Explanation: Since 25 is a perfect square, it is the closest perfect square to itself and absolute difference is 25-25=0. Iterate a loop j from i + 1 till N and perform the following: If A[j] > A[i]: next_greater = A[j] and break. Example 1: Input: N = 6, X = 16 Arr [] = {1, 4, 45, 6, 10, 8} Output: Yes Explanation: Arr [3]Max distance between same elements. The user can collect the value Vi + min (F (i+2, j), F (i+1, j-1) ) where [i+2,j] is the range of. World Cup Hack-A-Thon; GFG Weekly Coding Contest; Job-A-Thon: Hiring. Explanation: The first element smaller than 13 having index > 0 is 7. Algorithm: Initialize a variable ‘ count ‘ to 0 to keep track of the number of elements that satisfy the condition. The least next greater element of 6 is 9. If the absolute difference between arr[left] and target is less than or equal to the absolute difference between arr[right] and target, move left pointer one step to the right, i. Below is a Simple Method to solve this problem. This approach allows the. Swap the above found two digits, we get 53 6 97 4 in above example. In another word you have given an array, print the Next Greater Element (NGE) for every detail. 3. If n - a > b - n then the answer is b otherwise the answer is a. 4. -=. Input: N = 6 Arr [] = {5, 6, 2, 3, 1, 7} Output: -1 2 -1 1 -1 -1 Explanation: Next to 5 is 6 which is greater, so we print -1. Given an array arr [] of N integers and replace every element with the least greater element on its right side in the array. e, do n = n/2 iteratively. Example 1: Inpu. Back to Explore PageExamples: Input: a [] = {3, 4, 2, 7, 5, 8, 10, 6} q = 2. For. For 1, 5 is the greatest element in its left. C++. Your Task: You don't need to read input or print anything. If next is greater than the top element, Pop element from stack. For 6, there is only one smaller element on left side '1'. e . Whenever we pass through a cell, points in that cell are added to our overall points, the task is toGiven an array arr [] containing positive elements. Pick the rest of the elements one by one and follow the following steps in the loop. Therefore, all possible separation. In the flip operation, the leftmost node becomes the root of the flipped tree and its parent becomes its right child and the right sibling becomes its left child and the same should be done for all left most nodes recursively. 94, 0. Given an array Arr of N positive integers and another number X. Example 1: Input: N=6 arr[] = {3, 2, 1, 5, 6, 4} K = 2 Output: Yes Explanation: Every element is at most 2 distance away from its target. If it is not possible to find such. Add and Assign: Add right side operand with left side operand and then assign to left operand. Approach: The given problem is similar to that of finding the largest subtree sum in a tree. In case you need more clarity about a question, you may use the expected output button to see output for your given input. Count number of smaller elements on right side of each array element. If an element has no greater value on the right side, print -1. e first_half and second_half. Update the previous node’s value while the current node’s value is greater than the previous. A and B are two numbers defining a range. If there are no greater elements on the right side, replace it with -1. Ln 1, Col 1. Example 1: Input: S = 9 D = 2 Output: 18 Explanation: 18 is the smallest. Maximum Difference | Practice | GeeksforGeeks. Once we have the sorted list of node values, we can easily find the next. Traverse each element of the array using a. Distance = 6 – 2 = 4. If stack is not empty, compare top element of stack with next. Time Complexity: O(N 2) Auxiliary Space: O(1) Efficient Approach: To optimize the above approach, the idea is to use Two Pointer Approach. The second subarray contains points from P [n/2+1] to P [n-1]. Step 3: Eventually, the next in the stack is pushed. Solutions (2. The answer will be maximum node of two. Example 2: Input: N = 1500 Output: 1521 21 Explanation: Two of the. And extre. Third element 15 has nothing greater on the left side, so the answer is -1. If next is greater than the top element, Pop element from stack. Check if the largest value of the left subtree is less than the value of the root node and the smallest value of the right subtree is greater than the value of the root node, if this holds true, update the ans accordingly and return ans. Given an infix expression in the form of string str. Element with left side smaller and right side greater | Practice | GeeksforGeeks. round is used to round off the given digit which can be in float or double. The idea is based on the approach discussed in next greater element article. Try It! Method 1 (Simple): The naive approach is to run two loops and check one by one element of array check that array elements have at-least two elements greater than itself or not. Super star are those elements which are strictly. GfG Weekly + You = Perfect Sunday Evenings! Given a number N, the task is to find the largest prime factor of that number. Editorial. The Outer loop iterates through all the element and inner loop finds out whether the current index picked by the outer loop is equilibrium index or not. Approach: The given problem can be solved by using basic permutation and combination with the help of the following observations: The total number of ways to divide the given integer into two parts can be calculated as (Number of possible permutations) * (Ways to divide a permutation) => 9! * 8 => 2903040. The next higher number with two logic 1 bits is 17 (10001 2 ). 7. Given an array, find the next greater element for every element in the array (NGE). Given an array of integers, find the nearest smaller number for every element such that the smaller element is on the left side. Beginner level. If stack is not empty, compare top element of stack with next. Note: The order of precedence is: ^ greater than * equals to / greater than + equals to -. next is the next greater element for the popped. Level up from 1* to 2*. Can you solve this real interview question? Replace Elements with Greatest Element on Right Side - Given an array arr, replace every element in that array with the greatest element among the elements to its right, and replace the last element with -1. Ln 1, Col 1. ; Iterate a loop j from i + 1 till N and perform the following:. Solve company interview questions and improve your coding intellectOutput: 4. Fourth element 6 has 15 as the nearest greater element on the left, so the answer is 15 Similarly, we get values for the fifth and sixth elements. Node’s key is outside the given range. Print the value of ‘ans’ which represents the number of nodes whose left subtree average is greater than or equal to ‘K’. If an element has no greater or same value on the left side, print -1. Once the count becomes 2, we print the node. Feeling lost in the world of random DSA topics, wasting time without progress? It's time for a change! Join our DSA course, where we'll guide you on an exciting journey to master DSA efficiently and on schedule. So, the round up n (call it b) is b = a + 10. The nearest perfect square of arr [1] (= 2) is 1. Can you solve this real interview question? Find K Closest Elements - Given a sorted integer array arr, two integers k and x, return the k closest integers to x in the array. Loop while left < right a. GfG Weekly + You = Perfect Sunday Evenings! Register for free now. add (-1) 4. Beginner level. Since 2 is the first element and no element on its left is present, so it's greatest smaller element will be -1 and for 1 no element smaller than itself is present on its left, so it. For elements for which no next largest element exists, consider the next greater element as -1. Brute Force Approach. Example 2: Input: n = 6 a = {1, 5, 0, 3, 4, 5}. Given a circular integer array arr of size N (i. After that, add arr [i] to the Set S and print X if abs (X – arr [i]) is smaller than abs. !=, Not Equal to returns true if the left-hand side is not equal to the right-hand side. The first subarray contains points from P [0] to P [n/2]. All DSA Problems; Problem of the Day; GFG SDE Sheet; Curated DSA Lists. Else if arr [mid-1] is equal to x return mid-1. CSTT Driver Training is the leading driving school in Victoria, BC, we offer FREE ONLINE practice driving tests. If there is a leaf node having a value less than N, then element doesn’t exist and return -1. Step 3:Check if the inner loop element is less than the outer loop element. Now, find the nearest value smaller as well as greater than arr [i], say X and Y respectively. View nicmit's solution of Final Prices With a Special Discount in a Shop on LeetCode,. Approach: Follow the below steps to solve this problem: For the number N, find the nearest powers of K greater and smaller. Solve the selected problem successfully and this amount will be deducted automatically. Example 1: Input: N = 5, k = 2 arr[] = {12,5,787,1,23} Output: 787 23 Explanation: First largest element in the array is 787 and the second largest isAnother approach in O(1) auxiliary space and O(N) Time complexity: The idea to solve this problem is to traverse the string on and keep track of the count of open parentheses and close parentheses with the help of two counters left and right respectively. Ln 1, Col 1. All DSA Problems; Problem of the Day; GFG SDE Sheet; Curated DSA Lists. Output : 11 6 12 10 -1 20. Back to Explore Page. Menu. For element a [2] = 2 which has frequency = 2, NGF element is 1 at position = 6 with frequency of 3 > 2 4. 1 Time Machine costs 60 GeekBits. Run. (3) Divide the number n into two parts i. For example, next greater of the last element is always -1. Traverse the array from left to right until we find the maximum element. Back to Explore Page. Input: N = 24 Output: 3 Explanation: 24 has 2 prime factors 2 and 3 in which 3 is greater. Input: N = 4, arr [] = [1 3 2 4] Output: 3 4 4 -1. Input : n = 11 Output : Closest Greater = 13 Closest Smaller = 7. The idea is to apply Moore’s Voting algorithm, as there can be at max k – 1 elements present in the array which appears more than n/k times so their will. If arr [i] equals the number of elements after arr [i], it is a noble Integer. This is the best place to expand your knowledge and get prepared for your next interview. Hence possible parent of red node is a black node. Method 2 (Using Stack) Push the first element to stack. Given an array of integers, replace every element with the next greatest element (greatest element on the right side) in the array. The Next greater element for an element x is the first greater element on the right side of x in the array. GfG Weekly + You = Perfect Sunday Evenings! Register for free now . Then refuel from 0 liters to 60 units of fuels. Algorithm to search ceiling of x: 1) If x is smaller than or equal to the first element in array then return 0 (index of first element) 2) Else Linearly search for an index i such that x lies between arr [i] and arr [i+1]. Use two index variables l and r to traverse from left and right ends respectively. Key Pair | Practice | GeeksforGeeks. 61% Submissions: 217K+ Points: 2. VI). 11, 12, 19} Output: 0 7 Explanation: There are no elements less or equal to 0 and 7 elements greater or equal to 0. If no such positive integer exists, return -1. - undefined - LeetCode. After doing so, return the array. Given an array of integers A[] of length N and an integer target. Editorial. Initialize ans=[0,0,0] 4. The Brute Force Approach. World Cup Hack-A-Thon; GFG Weekly Coding Contest; Job-A-Thon: Hiring. For 1, 5 is the greatest element in its left. For example, next greater of the last element is always -1. 3 NGL | Nearest Greater to left Aditya Verma 183K subscribers Subscribe 2.